Question

Find p(x) when q(x)=x - 2,r(x)= 2x and g(x)=x^2+1​

Answer 1

YOUR ANSWER IS x³-2x²+3x-2.

EXPLANATION-

GIVEN:-

• q(x) = x-2 {Quotient}
• r(x) = 2x {Remainder}
• g(x) = x²+1 {Divisor}

To find:-

p(x) {Divident}.

Now,

By euclid's devision lema we get,

Divident = Divisor × Quotient + Remainder.

{a = bq+r}

---> p(x) = {(x²+1) × (x-2)} + 2x.

---> P((x) = (x³-2x² + x-2) + 2x.

---> P(x) = x³-2x²+x -2+2x.

---> P(x) = x³-2x²+3x-2.

Therefore the required value of p(x) is x³-2x²+3x-2.

Hope this will help you if it helps then plz mark my answer as BRAINLIEST. And remember to always keep a smile on face:)