find p0p1 of the polynomial pxis equal x23x2
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Step-by-step explanation:
The zeros of polynomial p(x)=x
2
−3x+2 can be given y p(x)=0
⟹x
2
−3x+2=0
x
2
−2x−x+2=0
x(x−2)−1(x−2)=0
(x−1)(x−2)=0
x=1,2
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