Question

Find pair of integers whose product is (‐36) and whose difference is 15.

Answer 1

it is said that x+y=-36
                      =y=-36-x
so x+y=-36 and it is also given that x-y=15
so x-(36-x)=15
    =x-36+x=15
    =2x-36=15
    =2x=15+36
    =2x=51
    =x=51\2
    x=25.5

1st number is 25.5

2nd number is 36-25.5=10.5
regards

Answer 2

According to the question
xy=(-36)
& x-y=15
⇒x=15+y

As xy=(-36) & x=15+y
⇒(15+y)y= -36
⇒y^2 + 15y = -36
⇒y^2 + 15y +36=0
Solving the equation you will get
y= -3 or y= -12
So if y is (–3) then x is 12 & if y is (–12) then x is 3.

Hope it helps..... :-)