find pair of integers whose product is -36 and whose diffrence is 15.
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the pair of integers whose product is -36 and whose difference is 15 are 12 and -3
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let the intigers be x and y
xy=-36 --(i)
x-y=15
x=15+y -- (ii)
from eq (i) and (ii) we get,
(15+y)y=-36
y^2 +15y -36 =0
y2+12y+3y-36
y(y-12)+ 3(y-12)
(y-12) (y+3)
y=12
x=27
xy=-36 --(i)
x-y=15
x=15+y -- (ii)
from eq (i) and (ii) we get,
(15+y)y=-36
y^2 +15y -36 =0
y2+12y+3y-36
y(y-12)+ 3(y-12)
(y-12) (y+3)
y=12
x=27
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