Question

find parametric equation of a parabola x=4-y^2 joining the point (0,-2) to the point (0,2)

Answer 1

Answer:

x=0

We have, x=t 2+1⇒x−1=t2

And y=2t+1⇒y−1=2t

Now (y−1)2=4t2=4(x−1)

⇒(y−1)2=4(x−1)

By comparing

a=1

So the directrix is, x−1=−a

⇒x=0