Find parametric equations for the line which is the intersection of the planes with equations
x+y+z=1
x-y+2z=0
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the equations of two planes are
x + y + z = 1 and x - y + 2 z =0
perpendiculars to these planes are given by the vectors :
( 1, 1, 1 ) or i + j + k (1, -1, 2 ) or i - j + k
cross product of these two vectors :
- i X j + i X k + j X i + j X k + k X i - k X j = 2 i + 0 j - 2 k or (2, 0, -2)
Let z = 0, then solving x + y +z = 1 and x - y +2 z = 0 gives,
(1/2 , 1/2, 0) is a point on both planes.
Equation of the line intersection of both planes and parallel to (2, 0 , -2) is:
x = 1/2 + 2 t, y = 1/2 + 0 t z = 0 + -2 t
or x = 1/2 + 2 t , y = 1/2 , z = -2 t
x + y + z = 1 and x - y + 2 z =0
perpendiculars to these planes are given by the vectors :
( 1, 1, 1 ) or i + j + k (1, -1, 2 ) or i - j + k
cross product of these two vectors :
- i X j + i X k + j X i + j X k + k X i - k X j = 2 i + 0 j - 2 k or (2, 0, -2)
Let z = 0, then solving x + y +z = 1 and x - y +2 z = 0 gives,
(1/2 , 1/2, 0) is a point on both planes.
Equation of the line intersection of both planes and parallel to (2, 0 , -2) is:
x = 1/2 + 2 t, y = 1/2 + 0 t z = 0 + -2 t
or x = 1/2 + 2 t , y = 1/2 , z = -2 t
kvnmurty:
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