Question

find perimeter and area of highlighted figure,that has semi circle diameter of 12m , rectangle of length 20m and breadth of 12m and right-angle triangle with sides 12m ,5m​

Answer 1

area of figure = area of semicircle + area of rectangle+ area of triangle

perimeter of figure = length of arc + 2×length of rectangle+ hypotenuse of traingle+base of traingle

area of semi circle = πr²/2

radius ,r=6m

area of semi circle= 22×36. 396.

———— =. ——— = 56.57

7×2. 7

area of rectangle = l×b = 20×12=240m

area of traingle = ½×b×h= ½×5×12=30m

area of the figure = 56.57+240+30= 326.57m

length of arc = πr = 6π=18.85

2×length of rectangle= 2×20=40

hypotenuse of traingle= √a²+b²=√12²+5²=√144+25=√169=13m

base of traingle= 5m

perimeter of the figure = 18.85+40+13+5=76.85