find perimeter and area of rectangle whose length 40 cm and diagonal 41 cm
Answers
Answered by
4
Answer:
(b) ^2 = ( h)^2 - ( l ) ^2
= ( 41) ^2 - ( 40 ) ^3
= 1681 - 1600
= 81
( b) ^2 = 81
b = 9 cm ..
perimeter of rectangle = 2( l + b )
= 2 ( 40 + 9 )
= 2(49)
= 98 cm
area of rectangle = l × b
= 40×9
= 360 cm^2
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Answered by
2
Answer:
Perimeter=
162 cm
Area=
1,640 cm
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