Question

find perimeter and area of rectangle whose length 40 cm and diagonal 41 cm​

Answer 1

Answer:

(b) ^2 = ( h)^2 - ( l ) ^2

= ( 41) ^2 - ( 40 ) ^3

= 1681 - 1600

= 81

( b) ^2 = 81

b = 9 cm ..

perimeter of rectangle = 2( l + b )

= 2 ( 40 + 9 )

= 2(49)

= 98 cm

area of rectangle = l × b

= 40×9

= 360 cm^2

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Answer 2

Answer:

Perimeter=

162 cm

Area=

1,640 cm