Question

find perimeter and area of rectangle whose length is 5.2 m and breadth is 2.3 m​

Answer 1

Answer:

perimeter of rectangle 2 (l+b)

2(5.2+2.3)

2(5.5)

11 is the perimeter of rectangle

Answer 2

Step-by-step explanation:

Question :-

• Find the perimeter and area of rectangle whose length is 5.2 m and breadth is 2.3 m.

To Find :-

• Perimeter of rectangle.
• Area of rectangle.

Solution :-

Given :

• Length = 5.2 m
• Breadth = 2.3 m

According to the question,

By using the formula,

${\sf{\longrightarrow Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}}$

Where,

• l = length
• b = breadth

Finding perimeter of rectangle :

${\sf{\longrightarrow Perimeter\ of\ rectangle\ =\ 2(l\ +\ b)}}$

${\sf{\longrightarrow 2(5.2\ +\ 2.3)}}$

${\sf{\longrightarrow2(7.5)}}$

${\sf{\longrightarrow 2 \times 7.5}}$

${\sf{\longrightarrow 15\ m}}$

$\therefore$ Hence, perimeter of rectangle is 15 m.

Now, let's find the area of rectangle.

$\rule{300}{2}$

By using the formula,

${\sf{\longrightarrow Area\ of\ rectangle\ =\ l \times b}}$

Where,

• l = length
• b = breadth

Finding area of rectangle :

${\sf{\longrightarrow Area\ of\ rectangle\ =\ l \times b}}$

${\sf{\longrightarrow 5.2 \times 2.3}}$

${\sf{\longrightarrow 11.96\ m^2}}$

$\therefore$ Hence, Area of rectangle is 11.96 m².

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$