find perimeter if rhombus whose diaganals are if 16 centimeter and 30 centimeter
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Given that the two diagonals are 30,and16,
⇒AO=302=15,BO=162=8,∠AOB=90∘
From Pythagorean theorem, we know
AB2=AO2+BO2
⇒AB=√152+82=√289=17
SInce AB=BC=CD=DA,
perimeter of ABCD=17⋅4=68
⇒AO=302=15,BO=162=8,∠AOB=90∘
From Pythagorean theorem, we know
AB2=AO2+BO2
⇒AB=√152+82=√289=17
SInce AB=BC=CD=DA,
perimeter of ABCD=17⋅4=68
sonu828:
thankyou a lot
Answered by
1
17*4=68.hope I helped u.
why we will multiply 17*4
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