Question

find perimeter of a rectangle whose length is 125cm and breadth is 60cm​

Answer 1

Answer:

Rectangle ABCD is consist two triangle.

Let triangle BCD has two sides equal AD=CD=60cm and AC=61cm

In ΔABC,

⟹(AC)

2

=(AB)

2

+(BC)

2

⟹(61)

2

=(60)

2

+(BC)

2

⟹(BC)

2

=3721−3600

⟹BC=

121

⟹BC=11cm

Hence, perimeter of the rectangle ABCD=25(AB+BC)

⟹2(60+11)

⟹2(71)

⟹142cm

Answer 2

Step-by-step explanation:

length of rectangle 125

breath of rectangle 60

perimeter 2×l+B

2×125+60

2×185

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