Math, asked by kaurrajwinder74605, 4 months ago

find perimeter of a rectangular field whose length is 4 times its width and which has area equal to 20736 square meters​

Answers

Answered by Anonymous
0

Answer:

720 m

Step-by-step explanation:

Let breadth be x

Length =4x

Area=20736m²

L×B=20736m²

4x×x²=20736m²

4x²=20736m²

x²=20736/4

x²=5184

x=72

Breadth=x

=72m

Length =4x

=4×72

=288

Perimeter =2(L+B)

=2(288+72)

=2(360)

=720m

Answered by sanjanapraveen26
3

Answer:

Perimeter of a rectangle =2(l+b)

l = 4b

area of the rectangle =20736

                             l×b   =20736

                        4b×b =20736

                              4b²=20736

                               b² =20736÷4

                               b ²= 5184

                               b   =√5184

                               b   =72

l = 4b

  = 4×72

  =288

perimeter = 2( l+b) = 2 (288+72)

                 = 2×360 =720

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