find perimeter of a rectangular field whose length is 4 times its width and which has area equal to 20736 square meters
Answers
Answered by
0
Answer:
720 m
Step-by-step explanation:
Let breadth be x
Length =4x
Area=20736m²
L×B=20736m²
4x×x²=20736m²
4x²=20736m²
x²=20736/4
x²=5184
x=72
Breadth=x
=72m
Length =4x
=4×72
=288
Perimeter =2(L+B)
=2(288+72)
=2(360)
=720m
Answered by
3
Answer:
Perimeter of a rectangle =2(l+b)
l = 4b
area of the rectangle =20736
l×b =20736
4b×b =20736
4b²=20736
b² =20736÷4
b ²= 5184
b =√5184
b =72
l = 4b
= 4×72
=288
perimeter = 2( l+b) = 2 (288+72)
= 2×360 =720
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