Question

Find perimeter of a rhombus in which diagonals are 24 cm and 10 cm.​

Answer 1

Answer:

side =v12^2+5^2 = 13

perimeter=13x4=52cm

Answer 2

Answer:

First we have to find the sides.

As the diagonals and side make a ∆, we have to use Pythagoras Theroem.

24/2 = 12. 10/2=5

${12}^{2} + {5}^{2} = side \: square \\ 144 + 25 = \sqrt{169 } \\ = 13$

So one side is 13 cm

Perimeter of rhombus = side × 4

Answer= 13×4= 52

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