Question

Find Perimeter of a square, whose area is
${121cm}^{2}$




​

Answer 1

Step-by-step explanation:

a² =121

a=11 cm

so the perimeter is 4a

4×11 = 44 cm

Answer 2

$\star \: \large\underline\mathtt{given : }$

$\sf{area \: of \: square \: = 121 \: cm {}^{2} }$

$\large\underline{ \star \: \mathtt{solution : }}$

$\sf{area \: of \: square = side {}^{2} } \\ \sf{side {}^{2} = 121 \: cm {}^{2} } \\ \sf{side = \sqrt{121cm {}^{2} } } \\ \underline{\sf{side = 11cm}}$

$\sf{perimeter \: of \: square \: = 4 \times side} \\ \sf{ = 4 \times 11 \: cm} \\ \sf{ = 44 \: cm} \\ \boxed{\sf{perimeter \: of \: square \: = 44cm}}$

hope it helps =)