Find perimeter of square if its diagonal is 10 root 2
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Answer: Hey there, hope it'll help you.
Please mark me as brainliest. : )
Step-by-step explanation:
Diagonal of a square = √(2a²) [where a= side of square]
So given: √(2a²)=10√2
or, 2a² = 100×2 [Squaring both side]
or, a² = 100
or, a=10
Now the perimeter of a square= 4a = 40
Answered by
1
Answer:
Step-by-step explanation:
Diagonal of sqaure = 10root2
The diagonal cuts the square into 2 triangles
So let sides of 1st triangle be
(Hypotenuse)2 = altitude 2 +base2
( 10root2 )2 = 2(base2)
200/2 = base2
100 = base2
Root(100) =base
Base or side of triangle = 10
Perimeter of square = 4(side)
= 4(10)
= 40cm
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