Find:-
Perimeter of the trapezium
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The perimeter will be
units
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Answer:
36 unit
Step-by-step explanation:
Here, BC = 10 unit, AD = 16 unit & AEB is a right angled traingle.
We should draw a line from C to ED and get a new point named F
So, EF = 16-BC = 16-10 = 10unit
And AE = DF = 6÷2 = 3unit
By the Pythagoras Theorem we will get AB² = AE²+BE²
AB² = 4²+3² = 16+9 = 25unit
AB = √25 = 5unit
Perimeter of the trapezium = AB+BC+CD+DF+FE+EA = 5+10+5+3+10+3 = 36unit
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