Math, asked by RushielMenon, 1 day ago

Find:-
Perimeter of the trapezium

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Answers

Answered by shivangsrivastava585
0

The perimeter will be

26 + 4 \sqrt{13}

units

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Answered by krsusantamanna
3

Answer:

36 unit

Step-by-step explanation:

Here, BC = 10 unit, AD = 16 unit & AEB is a right angled traingle.

We should draw a line from C to ED and get a new point named F

So, EF = 16-BC = 16-10 = 10unit

And AE = DF = 6÷2 = 3unit

By the Pythagoras Theorem we will get AB² = AE²+BE²

AB² = 4²+3² = 16+9 = 25unit

AB = √25 = 5unit

Perimeter of the trapezium = AB+BC+CD+DF+FE+EA = 5+10+5+3+10+3 = 36unit

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