Question

find perimeter of triangle whose vertices are (-2,1) (4,6) (6,3)​

Answer 1

Answer:

Let the vertices be A(-1,-2)B(2,1)C(-3,6)

AB= ( (3)^2+(3)^2 )^0.5 =3(2)^0.5

BC=((5)^2+ (5)^2)^0.5 = 5(2)^0.5

CA=((-3+1)^2 +(8)^2)^0.5 =(68)^0.5=2(17)^0.5

Hence the perimeter is sum of the sides =8(2)^0.5+2×(17)^0.5

Step-by-step explanation:

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