Question

find perpendicular component of a force of 16 Newton making an angle of 45 degree with x axis​

Answer 1

Explanation:

The perpendicular component of a force is Fsin@.

since it makes 45° with x-axis.

so perpendicular component of the force is =Fsin45°=16×(1/√2)=13.6N

Answer 2

Answer:

The perpendicular component will be Fsinθ = 16 × sin 45° = 16 × 1/root 2 = 8 root 2 N