Find PH of 0.05M Ba(oh)2 solution
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pOH = - log (OH)
= -log (0.05)
= 1.30
pH+POH=14
pH=14 - pOH
= 14 - 1.30
pH = 12.7
I hope it will correct and helpful.
= -log (0.05)
= 1.30
pH+POH=14
pH=14 - pOH
= 14 - 1.30
pH = 12.7
I hope it will correct and helpful.
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