Question

find pH of 10^(-2) Ba[lac]2 Solution .
if Ka= 10^(-5) ??​

Answer 1

Answer:

Barium hydroxide is a strong base.

Ba(OH)

2

⇌Ba

2+

+2OH

−

[OH

−

]=2×0.001M

pOH=−log[OH]=−log(2×10

−3

)=2.7

pOH+pH=14=14−2.7=11.3

∴pHof0.001MBa(OH)

2

is11.3