Find pH of 10^-5 M of NH4OH
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Explanation:
[OH
−
]=
K
b
×C
=
1×10
−5
×10
−1
=
10
−6
=10
−3
K
w
=[H
+
][OH
−
]
10
−14
=[H
+
][10
−3
]
[H
+
]=10
−11
Hence, pH=−logH
+
−log(1×10
−11
)=11
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