Question

find ph of mixture 200 ml Hcl ( ph = 2)and 800 ml Naoh (pH= 12)​

Answer 1

Answer:

Explanation:

ph1=2

h1=10^-2

ph2=12

poh=2

h2=10^-2

n1v1=10^-2*200

=2

n2v2=800*10^-2

=8

n2v2-n1v1/v1+v2

6/1000

oh- = 6/1000

-log oh-

-{-4+.77)

3.23

poh=3.23

ph=10.77