Find phythagorean triplet whose one member is 63
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Answer:
Let m^2 -1 = 63
=> m^2 = 64 => m = √64 = 8.
Numbers in phythagorean triplet:
2m = 16.
m^2 - 1 = 63.
m^2 + 1 = 65.
Phythagorean triplet is 16, 63 & 65.
✨Hope it will help you.✨
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