find plllllmshhsgeheh
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angleBDC=angleDBC(angles opposite to equal sides of a triangle are equal)
In triangle BCD,
angle BDC +angle DBC +BCD=180°
2 angle BDC +40°=180°
2angleBDC=140°
angle BDC=70°
it is clear that ABD is an equilateral triangle
so each angle =60°
angle ABD+angleBDC=angle ABC
60°+70°=angleABC
130°=angleABC
In triangle BCD,
angle BDC +angle DBC +BCD=180°
2 angle BDC +40°=180°
2angleBDC=140°
angle BDC=70°
it is clear that ABD is an equilateral triangle
so each angle =60°
angle ABD+angleBDC=angle ABC
60°+70°=angleABC
130°=angleABC
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