Find point of contact if line 3x+4y+20=0 touches circel x2 + y2 =16
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Answer:
point of contact is (x=> -36/15, y=> -16/5)
Step-by-step explanation:
given, 3x+4y+20=0
=> x = -(4y+20)/3 (A)
substituting in x² + y² = 16
(16y² + 400 + 160y)/9 + y² = 16
16y² + 400 + 160y + 9y² = 144
25y² + 160y + 256 = 0
(5y+16)² = 0
y = - 16/5
from (A) , x = -(-4x16/5 +20)/3 = -36/15
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