Find point on x-axis
on x-axis each of which is at a
10 with from the
dist
point( 11,-8).
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Answer:
Let P (X,0) be the point on the X-axis
Then as per the question we have
AP =10
=under square root (x-11)²+(0+8)²=10
(x-11)²+8²=100
(x-11)²=100-64=36
x-11=±6
x=11±6
x=11-6,11+6
x=5,17
Hence the points on the X-axis are (5,0)and(17,0)
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