Math, asked by isikamaheshwari, 7 months ago

Find point on x-axis
on x-axis each of which is at a
10 with from the
dist
point( 11,-8).​

Answers

Answered by ajaykumarsingh038
1

Answer:

Let P (X,0) be the point on the X-axis

Then as per the question we have

AP =10

=under square root (x-11)²+(0+8)²=10

(x-11)²+8²=100

(x-11)²=100-64=36

x-11=±6

x=11±6

x=11-6,11+6

x=5,17

Hence the points on the X-axis are (5,0)and(17,0)

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