Question

Find point on x axis which is equidistant -2,5 and 2,9

Pls fast

Answer 1

Answer:

Step-by-step explanation:We have to find a point on x-axis. Therefore, its y-coordinate will be 0.

Let the point on x-axis be (x,0)image

(x - 2)2 + 25 = (x - 2)2 + 81

x2 + 4 - 4x + 25 = x2 + 4 + 4x + 81

8x = 25 -81

8x = -56

x = -7

Therefore, the point is ( - 7, 0).We have to find a point on x-axis. Therefore, its y-coordinate will be 0.

Let the point on x-axis be (x,0)image

(x - 2)2 + 25 = (x - 2)2 + 81

x2 + 4 - 4x + 25 = x2 + 4 + 4x + 81

8x = 25 -81

8x = -56

x = -7

Therefore, the point is ( - 7, 0)