Question

find point on x axis whinh is eqi distant from points (5,-2), (-3,2)

Answer 1

Step-by-step explanation:

point on y-axis x=0

point=(0,y)

equidistant from (5,-2) and(-3,2)

distance from first point=(25+y^2+y-4y)^1/2

distance from second point=(9+y^2+4-4y)^1/2

both equals

squaring both

29+y^2+4y=13+y^2-4y

8y=-16

y=-2

point=(0,-2)

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Answer 2

Point on y-axis x=0

point=(0,y)

equidistant from (5,-2) and(-3,2)

distance from first point=(25+y^2+y-4y)^1/2

distance from second point=(9+y^2+4-4y)^1/2

both equals

squaring both

29+y^2+4y=13+y^2-4y

8y=-16

y=-2

point=(0,-2)

Hope it helps you,

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