Question

find point y axis which is at equidistance from A(2,3) and B(1,4)​

Answer 1

Answer:

answer is (0,2)

Step-by-step explanation:

Given: A(2,3) and B(1,4)

If the point is on y axis it's co-ordinates would be (0,y)

apply the distance formula:

√(0-2)²+(y-3)² = √(0-1)²+ (y-4)²

√(-2)²+(y-3)² = √(-1)²+ (y-4)²

√4 + (y-3)² = √1+ (y-4)²

Squaring both sides:

4 + (y-3)² = 1+ (y-4)²

4 + y² +9 -6y = 1 +  y² +16 -8y

y² +9 -6y -  y² -16 +8y = 1 - 4

-7 + 2y = -3

2y = -3+7 = 4

y = 4/2 = 2

Hence, the answer is (0,2).

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