Math, asked by RinoyR35821, 10 months ago

Find points on line which are at 1 unit distance

Answers

Answered by Anonymous
12

Step-by-step explanation:

Step 1

The coordinates of the arbitrary point on x+y=4 can be obtained by putting x=t (or y=t) and then obtaining y(or x) from the equation of the line, where t is a parameter.

Substituting x=t in x+y=4 we get

y=4−t

∴ The coordinates of an arbitrary point on the given line are P(t,4−t).

Let P(t,4−t) be the required point.

Step 2

It is given that the distance of P from the line 4x+3y−10=0 is unity.

∴∣∣∣4t+3(4−t)−1042+32−−−−−√∣∣=1

(i.e) |t+2|=5

(i.e) t+2=±5

∴t=−7ort=3

Hence the required points are (-7,11) or ( 3,1)

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