Find points on the line x + y -4 = 0 which
are at one unit distance from the line
x + y - 2=0
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Number of points = 0
The given lines x + y -4 = 0 and x + y - 2=0 are parallel as both the given lines have equal slope(slope= -1).
For x + y -4 = 0 -
A = 1 , B = 1 , c1 = -4
For x + y - 2 = 0 -
A = 1 , B = 1 , c1 = -2
Distance between two parallel line , d = |c1 - c2|/√(A²+B²)
=> |-4 + 2|/√2
=> 2/√2
=> √2
The distance between the two lines is equal to √2 units , so no such point is possible that lies on x + y -4 = 0 is at one unit distance from the line
x + y - 2=0.
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