CBSE BOARD X, asked by Mesha3362, 1 year ago

Find points on the x-axis, each of which is at a distance of 10 units from the point P(11, -8) with proper steps.

Answers

Answered by abhayspandey
5

Answer:

Let the point on X axis be A(x,0),then,

AP=10

AP^2=10^2,

(x-11)^2+(0-(-8)^2=10^2

x^2-22x+121+64=100

x^2-22x+185-100=0

x^2-22x+85=0

X^2-17x-5x+85=0

x(x-17)-5(x-17)

(x-17)(x-5)

x-17=0

x=17

x-5=0

x=5

hence, the required points are(17,0)and(5,0).

Answered by varshabnair5
1

Answer:

Explanation:

Let the point on X axis be A(x,0),then,

AP=10

AP^2=10^2,

(x-11)^2+(0-(-8)^2=10^2

x^2-22x+121+64=100

x^2-22x+185-100=0

x^2-22x+85=0

X^2-17x-5x+85=0

x(x-17)-5(x-17)

(x-17)(x-5)

x-17=0

x=17

x-5=0

x=5

hence, the required points are(17,0)and(5,0).

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