find points where the graph of the equation 3x+4y=12cuts the x-axis and y-axis
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Let the point which cuts x-axis be(a,0)
the point which cuts the y-axis be (0,b)
the given equation is3x+4y=12
cutting x-axis: 3x+4(0)=12
x=4
the point is (4,0)
cutting y-axis : 3(0)+4y=12
y=3
the point is (0,3)
the point which cuts the y-axis be (0,b)
the given equation is3x+4y=12
cutting x-axis: 3x+4(0)=12
x=4
the point is (4,0)
cutting y-axis : 3(0)+4y=12
y=3
the point is (0,3)
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