Question

find Polar form of complex number z=(i)^75 answer it fast
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Answer 1

Answer:

⇒z=−i. So, we got, z=i75=−i. We know that the polar form of a complex number, z as z=r(cosθ+isinθ), where r=|z| and θ=arg(z). We got z=−i, which can be written in the form of, z=x+iy⇒z=0−i, where real part x is zero and the imaginary part is (-i).