Find poly. Whose zeros are 5+√19and 5-√19
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We know that sum of zeroes= -b/a
So,
5 + √19 + 5 - √19
= 10
Therefore -b/a= 10
b= -10 and a= 1
Now Product of zeroes is c/a
( 5 + √19) ( 5- √19)
=5² - √19² ( a²- b² = (a+b) (a-b) )
=25- 19
=6
c= 6
The polynomial will be of the form ax² + bx + c = 0
Substituting the values, we get
p(x) = x² - 10x + 6
So,
5 + √19 + 5 - √19
= 10
Therefore -b/a= 10
b= -10 and a= 1
Now Product of zeroes is c/a
( 5 + √19) ( 5- √19)
=5² - √19² ( a²- b² = (a+b) (a-b) )
=25- 19
=6
c= 6
The polynomial will be of the form ax² + bx + c = 0
Substituting the values, we get
p(x) = x² - 10x + 6
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Hiii
Here is the solution hope u may understand
Here is the solution hope u may understand
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