Question

Find polynomial whose zeroes are 2/3 and 3/2​

Answer 1

Answer:

let p(x) be the polynomial whose zeroes are 2/3 and 3/2.

we will find sum and product of zeroes in order to find p(x).

$sum \: of \: zeroes = \frac{2}{3} + \frac{3}{2} \\ = \frac{4 + 9}{6} \\ = \frac{13}{6}$

and

$product \: of \: zeroes = \frac{2}{3} \times \frac{3}{2} \\ = 1$

Now,

p(x) = x²-(sum of zeroes)x+(product of zeroes)=0

$= > {x}^{2} - \frac{13}{6} x + 1 = 0$

$= > \frac{6 {x}^{2} - 13x + 6 }{6} = 0$

$= > 6 {x}^{2} - 13x + 6 = 0 \: is \: the \: req \: polynomial.$

Answer 2

Answer:

this is your answer

Step-by-step explanation:

hope it helps you