Question

find positive integer whose cube exceeds it's square by 4624​

Answer 1

Answer:

17

Step-by-step explanation:

Find the positive integer whose cube exceeds its square by 4624.

Let say number = X

Than cube = X³

X³ = X² + 4624

=> X³ - X² - 4624 = 0

=> X³ - 17X² + 16X² - 272X + 272X - 4624 = 0

=> X²(X - 17) + 16X(X - 17) + 272(X - 17) = 0

=> (X - 17) (X² + 16X + 272) = 0

=>  X = 17    

for X² + 16X + 272  D < 0 so no real solution

only Positive integer satisfying is 17

Answer 2

Answer:

17

Step-by-step explanation: