Question

find Positive value for m for which the distance between the points A(5, - 3) and B (13, M) is 10 units

Answer 1

Answer:

Step-by-step explanation:

(m+3)^2+64=100

m^2+6m+73=100

m^2+6m-27=0

by factorizing m=3,-9

m=3

Answer 2

Answer:         3

Step-by-step explanation:

                   By distance formula,

       d(A,B) = √[(13-5)² + (M-(-3))²]

             10 = √[ 8² + (M+3)²]..........(given)

             10 = √[ 64 + (M+3)²]

                  squaring both the sides,

           100 = 64 + (M+3)²

           100 = 64 + M² + 6M + 9

               0 = 73 - 100 + M² + 6M

               0 = M² + 6M - 27

               0 = M² + 9M - 3M - 27

               0 = M (M+9) - 3(M+9)

               0 = (M+9) (M-3)

        M+9=0   or   M-3=0

        M = -9    or   M = 3

    therefore, Positive value for M is 3.