find potential at a distance of 12 cm from a charged cylinder , charge density is 4 m µC per cm, radius of the cylinder is 4 cm
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Answer:
Explanation:
Magnitude of E.ds=
ϵ
0
q
rms
Q
E
=AE
Combining this and we get,
2ϵ
0
d
ρr
2
.
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