find pressure.. if mass of the rectangle is 10 kg and the sides are 5 cm and 2cm respectively .
Answers
Answer:
The max pressure would be 13333.33 Pa and minimum would be 2000 Pa
1) Mass of cuboid = 2 kg
and g = 10 m/ s^2
The force exerted by the cuboid would be
F = mg = 2*10 = 20 N
2) The formula for pressure is
P = F/A
Hence, pressure is inversely proportional to the area i.e. minimum the area, higher would be the pressure and vice versa
3) The area of three sides of the cuboid would be
3*5 = 15 cm^2 = 0.0015 m^2
5*20 = 100 cm^2 = 0.01 m^2
3*20 = 60 cm^2 = 0.06 m^2
4) Hence, pressure would be minimum at side with dimensions 5 and 20
P = 20/0.01 = 2000 Pa
Pressure would be maximum at side with dimension 3 and 5
P = 20/ 0.0015 = 13333.333 Pa
mass = 10kg
Force = mass * acceleration
= 10 * 9.81 = 98.1 kg
area of the rectangle = length * breadth = 0.05 m * 0.02m = 0.0010m^2
pressure = force/area
= 98.1 kg/ 0.0010m^2
= 98,100 kg/m^2