Question

find pressure, when a thrust of 20N is applied on a surface area of 10cm^2​

Answer 1

Answer:

p =F/A

p=20/10×10^-2

p=20×10=200 Nm^2

Answer 2

Answer:

$pressure \: = \: \frac{force}{area}$

$= \frac{20 \: }{ {10}^{ - 3} }$

$= 2 \times {10}^{4} pascals$