Question

Find pretcentage of each compound inCuSo45H2O

Answer 1

Answer:

The molecular weight of water H2O=2(1)+16=18. When 1 mole of CuSO4⋅5H2O is heated, 5 moles of water are lost. Percentage loss of mass of CuSO4⋅5H2O=25090×100=36 %.

Answer 2

Given the compound is Copper Sulphate Pentahydrate,

Here, there are two compounds: CuSO₄ and H₂O,

R.M.M of Cu = 63.5 g, S = 32 g, O = 16 g, H = 1 g,

Molar Mass = 63.5+32+(16*4)+5*18

= 249.5 g

% composition of CuSO₄ = (63.5+32+64)/249.5*100 %

= 159.5/249.5*100%

= 63.92%

% composition of H₂O = 90/249.5*100%

= 36.07%

I hope this helps.