Math, asked by aditi201074, 2 days ago

Find prime factorization of 945
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Answered by sudarshansinghsam
4

Answer:

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Answered by Anonymous
12

Answer:

Factors of 945 are the list of integers that we can split evenly into 945. There are overall 16 factors of 945, of which 3, 5, 7 are its prime factors. The sum of all factors of 945 is 1920.

The number 945 is composite and therefore it will have prime factors. Now let us learn how to calculate the prime factors of 945. The first step is to divide the number 945 with the smallest prime factor, here it is 3. We keep dividing until it gives a non-zero remainder.

945 ÷ 3 = 315

315 ÷ 3 = 105

105 ÷ 3 = 35

Further dividing 35 by 3 gives a non-zero remainder. So we stop the process and continue dividing the number 35 by the next smallest prime factor. We stop ultimately if the next prime factor doesn't exist or when we can't divide any further.

So, the prime factorization of 945 can be written as 3¹ × 5¹× 7¹ where 3, 5, 7 are prime.

prime factorization of 945:3,5,7

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