Find principal and general solution of cotx = √3
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1
Answer:
nπ+
6
5π
,n∈Z.
Step-by-step explanation:
cotx=−
3
We know, cot
6
π
=
3
Therefore, cot(π−
6
π
)=−cot
6
π
=−
3
and cot(2π−
6
π
)=−cot
6
π
=−
3
cot
6
5π
=−
3
and cot
6
11π
=−
3
Therefore, the principal solutions are x=
6
5π
and
6
11π
.
Now, cotx=cot
6
5π
tanx=tan
6
5π
x=nπ+
6
5π
Therefore, the general solution is x=nπ+
6
5π
,n∈Z.
hope it's helpful to you
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