Question

Find principal value :
Cot-(-1/13)-Sec" (-2/V3)​

Answer 1

Answer:

make the answer by hint:

Step-by-step explanation:

12th

Maths

Inverse Trigonometric Functions

Inverse Trigonometric Functions

Find the principal value of...

MATHS

Find the principal value of tan

−1

3

−sec

−1

(−2).

HARD

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VIDEO EXPLANATION

ANSWER

Let tan

−1

3

=x that is

tanx=

3

=tan

3

π

Therefore, x=

3

π

∈[−

2

π

,

2

π

]

Now let sec

−1

(−2)=y that is secy=−2.

Therefore, y=−sec

3

π

that is

secy=sec(π−

3

π

)=sec

3

2π

Thus, y=

3

2π

∈[0,π]−(

2

π

)

Now consider tan

−1

3

−sec

−1

(−2) as shown below:

tan

−1

3

−sec

−1

(−2)=x−y=

3

π

−

3

2π

=−

3

π

Hence, tan

−1

3

−sec

−1

(−2)=−

3

π

.