Question

find principle value of sec-1 (-2/√3)​

Answer 1

Answer:

Let y = sec¹ {_2_}

{√3}

sec y = (. π. )

_

( 6. )

range of principal value

of sec. -1 is {0,π} - {π}

{-}

{2}

hence principal value-1(2) is π

(√3) -

6

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