Question

find probability of a 5 turning up at least once in two tosses of a fair die

Answer 1

2 Tosses : 2 Heads , 2 Tails ( HT, HH, TH, TT)

total number of outcomes = 4
total number of favourable outcomes = 5

THEN,
P( coins) = 4/5

Answer 2

Answer:

The probability of turning up of 5 = 0.31

Step-by-step explanation:

Probability: Probability is the chance of occurring any incident.

• The probability  of an event to occur = $\frac{Number of favorable outcomes }{Total Number of Outcomes}$
• Example: Suppose there are 6 red balls, 4 green balls and 2 black balls in a box.

       Total number of outcomes = 6 + 4 + 2 = 12

       Now the probability of picking red ball once = $\frac{6}{12}$ = 0.5

       Now the probability of picking green ball once = $\frac{4}{12}$ = 0.33

       Now the probability of picking black ball once = $\frac{2}{12}$ = 0.16

• Solution: A die has 6 sides : 1, 2, 3, 4, 5, 6.

        If the die is thrown twice,  then total number of outcomes = 6 × 6

                                                                                                         = 36

      The favorable outcomes = turning up of 5 = 11

      [(1,5),(2,5),(3,5),(4,5),(5,5),(5,6),(6,5),(5,4),(5,3),(5,2),(5,1)]

      The probability of turning up of 5  = $\frac{Number of favorable outcomes }{Total Number of Outcomes}$

                                                               = $\frac{11}{36}$ = 0.31