Question

find probability of getting 53 sunday on leap year class 9 question
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Answer 1

ln a non-leap year there will be 52 Sundays and 1 day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday, friday , Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.

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Answer 2

Answer:

The possible pairs are ( Saturday, Sunday) and (Sunday, Monday), So n(E) =2. Therefore the probability of a leap year having 53 Sundays = n(E)/n(S) = 2/7.

Step-by-step explanation:

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