Question

Find probability of getting 53 sundays in non leap year

Answer 1

A non - leap year consists of 365 days.

In 365 days = 52 weeks and 1 day remaining.

For 52 weeks, there will be 52 Sunday. The remaining one day may be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.

Total 7 outcomes. The favorable outcomes is only 1.

So, the probability is 1/7.

Hope it is helpful.

Answer 2

Answer:

We know that A non-leap year consists of 365 days.

In 365 days, Number of weeks = 52 and 1 day remaining.

For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.

Out of these 7 total outcomes, the favorable outcomes are 1.

Hence the probability of getting 53 Sundays = 1/7.

Hope this helps!