find probability of getting 53sundays in a leap year
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The probability of a year being a leap year is 1/4
A leap year has 366 days or 52 weeks and 2 odd days.
The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.
So there are 7 possibiliyies out of which 2 have a Sunday.
So the probability of 53 Sundays in a leap year is 2/7.
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A leap year has 366 days or 52 weeks and 2 odd days.
The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.
So there are 7 possibiliyies out of which 2 have a Sunday.
So the probability of 53 Sundays in a leap year is 2/7.
I hope it is helped you
follow me
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